C语言机试编程题
编写版本：vc++2022
1.求最大/小值
#include<stdio.h>
int main(){int a[50],n;int max, min;printf("请输入您要输入几个数");scanf_s("%d", &n);printf("请输入您要比较的%d个数\n",n);for (int i = 0; i<n; i++) {scanf_s("%d", &a[i]);}max = min = a[0];for (int i = 0; i < n; i++) {if (a[i] > max) max = a[i];if (a[i] < min) min = a[i];}printf("max=%d,min=%d", max, min);return 0;
}2.求一个三位数abc，使a的阶乘+b的阶乘+c的阶乘=abc
#include<stdio.h>
//factorial 阶乘
int jiecheng(int n) {int m=1;while (n != 0) {m *= n;n--;}return m;
}
int main() {int a, b, c;for (int abc = 100; abc <= 999; abc++) {a = abc / 100;b = abc / 10 % 10;c = abc % 10;if (abc == jiecheng(a) + jiecheng(b) + jiecheng(c))printf("%d\n", abc);}return 0;
}3.求2/1，3/2，5/3，8/5，13/8，21/13，的前20项和
#include<stdio.h>
int main() {float sum = 2;int i = 1, j = 2;float k;for (int num = 1; num < 20; num++) {k = i + j;i = j;sum += k / i;j = k;}printf("%0.2f", sum);return 0;
}4.求阶乘
#include<stdio.h>
int main() {int N;int jiecheng=1;scanf_s("%d", &N);while (N != 0) {jiecheng *= N;N--;}printf("%d\n", jiecheng);return 0;
}5.求10-1000之间所有数字之和为5的整数的个数
#include<stdio.h>
int main() {int count = 0;for (int i = 10; i <= 99; i++) {//两位数if (i/10+i%10== 5)count++;}for (int i = 100; i <= 999; i++) {//三位数if ((i/100)+(i/10%10)+(i%10)== 5)count++;}printf("%d\n", count);return 0;
}6.输入字符串打印除小写，元音，字母之外的。用数组
#include<stdio.h>
int main() {char a[50];scanf_s("%s", a, 50);for (int i = 0; a[i] != '\0'; i++)if (a[i] != 'a' && a[i] != 'e' && a[i] != 'i' && a[i] != 'o' && a[i] != 'u')printf("%c", a[i]);return 0;
}scanf_s输入字符串时，需要添加长度防止溢出
7.计算输入的10个整数中的，偶数的和，偶数平均值（小数表示）
#include<stdio.h>
int main() {int a[10];int sum=0;double avg;for (int i = 0; i < 10; i++) {scanf_s("%d", &a[i]);if (a[i] % 2 == 0) sum += a[i];}avg = sum / 10.0;printf("偶数的和%d,偶数的平均值%0.2f", sum, avg);return 0;
}8.循环语句求a+aa+aaa+aaaa……n个a，n和a由键盘输入
#include<stdio.h>
#include<math.h>
int main() {int a, n,m;int sum = 0;scanf_s("%d %d", &a, &n);m = a;for (int i = 1; i <= n; i++) {sum += m;m += a * pow(10, i);}printf("%d", sum);return 0;
}9.1！+2！+3！+4！……
#include<stdio.h>
int main() {int sum = 0, n,m=1;scanf_s("%d", &n);for (int i = 1; i <= n; i++) {m *= i;sum += m;}printf("%d", sum);return 0;
}10.求sum=1-1/3+1/5-1/7+ +1/n（1/n<0.0001)
#include<stdio.h>
int main() {float sum = 0;int k=1;for (int i = 1; (1.0 / i) >= 0.0001; i += 2) {sum += (1.0 / i) * k;k = -k;}printf("%0.2f", sum);return 0;
}11.输入正数判断是否为素数
#include<stdio.h>
int main() {int i,n;scanf_s("%d", &n);//素数：=质数，除了1和它本身之外不能被其他数整除。否则称为合数（1既不是质数也不是合数）if (n == 1) printf("%d不是素数", n);else if (n == 2) printf("%d是素数", n);else {for (i = 2; i < n; i++) {if (n % i == 0) {printf("%d不是素数", n);break;}}if(i>=n) printf("%d是素数", n);}return 0;
}12.编写一个计算器，可以计算+-*/
#include<stdio.h>
int main() {float a, b;char ch;scanf_s("%f", &a);ch = getchar();scanf_s("%f", &b);switch (ch) {case '+':printf("=%0.2f", a + b); break;case '-':printf("=%0.2f", a - b); break;case '*':printf("=%0.2f", a * b); break;case '/':printf("=%0.2f", a / b); break;}return 0;
}13.求m，n的最小公倍数
#include<stdio.h>
int main() {//lcm:lowest common multiple 最小公倍数int m, n,min;scanf_s("%d %d", &m, &n);if (m < n) min = m;else min = n;for(int i=min;i<=n*m;i++)if (i % m == 0 && i % n == 0) {printf("最小公倍数：%d", i);break;}return 0;
}14.对10个数排序
#include<stdio.h>
int quick_one_pass(int a[], int low, int high) {int mid = a[low];while (low < high) {while (low < high && a[high] >= mid) --high;a[low] = a[high];while (low < high && a[low] <= mid) ++low;a[high] = a[low];}a[low] = mid;return low;
}
void quicksort(int a[], int low, int high) {int k;if (low < high) {k = quick_one_pass(a, low, high);quicksort(a, low, k - 1);quicksort(a, k + 1, high);}
}
int main() {//快速排序int a[10] = { 2,6,4,8,1,9,3,5,7,4 };quicksort(a, 0, 9);for (int i = 0; i < 10; i++)printf("%d ", a[i]);return 0;
}